Reply #34: This has been discussed on DU several times. [View All]

In short, right now the 495,304 people in Wyoming have three electoral votes, due to the fact that they have two Senators and one Representative. That's one electoral vote for 165,101 people.

The 33,930,798 people in California have 54 electoral votes. That's one electoral vote for 616,924 people.

That means a voter in Wyoming has 3.74 times the Presidential voting power of a voter in California.

In actuality, that disproportionate voting power goes far beyond just Presidential elections due to the manner in which Congress proposes and passes legislation.

Today, the average number of people represented by one member of the House is 646,947. In 1790, it was 37,068. In 1910, when the House grew to 435 seats, it was 212,020.

Here's a table of Electoral Voting Power in relation to the 'average':
01 3.19 Wyoming
02 2.59 Vermont
03 2.51 Alaska
04 2.45 North Dakota
05 2.08 South Dakota
06 2.01 Delaware
07 2.00 Rhode Island
08 1.74 Montana
09 1.73 Hawaii
10 1.70 New Hampshire
11 1.65 Maine
12 1.62 Idaho
13 1.53 Nebraska
14 1.45 West Virginia
15 1.44 New Mexico
16 1.31 Nevada
17 1.26 Iowa
18 1.18 Arkansas
19 1.18 Utah
20 1.17 Kansas
21 1.11 Mississippi
22 1.10 Colorado
23 1.08 Connecticut
24 1.07 Oregon
25 1.07 Minnesota
26 1.06 Oklahoma
27 1.06 Alabama
28 1.06 Louisiana
29 1.05 South Carolina
30 1.04 Kentucky
31 1.03 Missouri
32 1.02 Arizona
33 1.02 Tennessee
34 0.99 Massachusetts
35 0.99 Maryland
36 0.98 Wisconsin
37 0.98 Washington
38 0.98 North Carolina
39 0.96 Virginia
40 0.96 Georgia
41 0.95 Indiana
42 0.94 New Jersey
43 0.92 Ohio
44 0.90 Michigan
45 0.90 Pennsylvania
46 0.89 Illinois
47 0.89 Florida
48 0.86 New York
49 0.86 Texas
50 0.85 California